(1/9)^2x+7=27^6x-12

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Solution for (1/9)^2x+7=27^6x-12 equation:



(1/9)^2x+7=27^6x-12
We move all terms to the left:
(1/9)^2x+7-(27^6x-12)=0
Domain of the equation: 9)^2x!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+1/9)^2x-(27^6x-12)+7=0
We get rid of parentheses
(+1/9)^2x-27^6x+12+7=0
We multiply all the terms by the denominator
(+1-27^6x*9)^2x+12*9)^2x+7*9)^2x=0
Wy multiply elements
972x^2+(+1-27^6x*9)^2x=0

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